Hello there

Im having a problem running a very simple piece of code in Excel v15.18 for Mac, that works on Windows:

Sub RemoveDups2()

    Range("L18").Select
' L collum has a funtion =IF(K18=K19; 1;0)
' From L18 to end of list there are only 3 possible values
' 0 for ok, 1 for duplicate and nothing for end of list


    Do Until ActiveCell = ""
        ActiveCell.Offset(1, 0).Select


        If ActiveCell.Value = "1" Then .EntireRow.Delete


        End If
    Loop


End Sub
The error:

Compilation error:


invalid reference or not qualified
(Module1 258:39)
The error seems to happen at 
.EntireRow.Delete
but i dont know how to fix something that should be working :P

I also have another piece of code that could replace mine entirely, made by another user here (Thanks JKwan) that again, works on windows but not on mac:

ption Explicit
Sub RemoveDup()
'
' RemoveDup Macro
'


'


    Dim Lastrow As Long
    Dim Lrow As Long
    Dim WSInput As Worksheet
     
    Set WSInput = ThisWorkbook.Worksheets("Sheet1")
    Lastrow = FindLastRow(WSInput, "D")
    On Error GoTo Dup
    With CreateObject("scripting.dictionary")
        For Lrow = Lastrow To 18 Step -1
            .Add Trim(WSInput.Cells(Lrow, "K")), Trim(WSInput.Cells(Lrow, "K"))
        Next Lrow
    End With
     
    On Error GoTo 0
    Set WSInput = Nothing
    Exit Sub
     
Dup:
    Rows(Lrow & ":" & Lrow).Delete
    Resume Next
End Sub
Function FindLastRow(ByVal WS As Worksheet, ColumnLetter As String) As Long
    FindLastRow = WS.Range(ColumnLetter & Rows.Count).End(xlUp).Row
End Function
And in this case the error is:

Microsoft Visual Basic

execution time error "13":


correspondency error

This time the error happens at : 
Rows(Lrow & ":" & Lrow).Delete
I assume its something to do with the .Delete parameter but, hey what do i know? xP

Thanks in advance for the support